Return ratio

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The return ratio of a dependent source in a linear electrical circuit is the negative of the ratio of the current (voltage) returned to the site of the dependent source to the current (voltage) of a replacement independent source. The terms loop gain and return ratio are often used interchangeably; however, they are necessarily equivalent only in the case of a single feedback loop system with unilateral blocks. ^[1]

Calculating the return ratio[edit]

The steps for calculating the return ratio of a source are as follows:^[2]

1. Set all independent sources to zero.
2. Select the dependent source for which the return ratio is sought.
3. Place an independent source of the same type (voltage or current) and polarity in parallel with the selected dependent source.
4. Move the dependent source to the side of the inserted source and cut the two leads joining the dependent source to the independent source.
5. For a voltage source the return ratio is minus the ratio of the voltage across the dependent source divided by the voltage of the independent replacement source.
6. For a current source, short-circuit the broken leads of the dependent source. The return ratio is minus the ratio of the resulting short-circuit current to the current of the independent replacement source.

Other methods[edit]

The above steps can be implemented in SPICE simulations by replacing non-linear devices by their small-signal model equivalents. These steps are not feasible where dependent sources inside devices are not directly accessible, for example, when SPICE itself is used to generate the small-signal circuit numerically, or when measuring the return ratio experimentally. When small-signal models cannot be used, an added problem is finding how to break a a loop without affecting the bias point and altering the results. Middlebrook^[3] and Rosenstark^[4] have proposed several methods for experimental evaluation of return ratio (loosely referred to by these authors as simply loop gain), and similar methods have been adapted for use in SPICE by Hurst.^[5][6] or Roberts,^[7] or Sedra,^[8] and especially Tuinenga.^[9]

Example: Collector-to-base biased bipolar amplifier[edit]

(PD) Image: John R. Brews
Collector-to-base biased bipolar amplifier.

(PD) Image: John R. Brews
Left - small-signal circuit corresponding to bipolar amplifier; Center - inserting independent source and marking leads to be cut; Right - cutting the dependent source free and short-circuiting broken leads.

The figure at right shows a bipolar amplifier with feedback bias resistor R_f driven by a Norton signal source. In the tableaux of small-signal circuits, the left panel shows the corresponding small-signal circuit obtained by replacing the transistor with its hybrid-pi model. The objective is to find the return ratio of the dependent current source in this amplifier.^[10] To reach the objective, the steps outlined above are followed. The center panel shows the application of these steps up to Step 4, with the dependent source moved to the left of the inserted source of value i_t, and the leads targeted for cutting marked with an X. The right panel shows the circuit set up for calculation of the return ratio T, which is

${\displaystyle T=-{\frac {i_{r}}{i_{t}}}\ .}$

The return current is

${\displaystyle i_{r}=g_{m}v_{\pi }\ .}$

The feedback current in R_f is found by current division to be:

${\displaystyle i_{f}={\frac {R_{D}{\mathit {\parallel }}r_{O}}{R_{D}{\mathit {\parallel }}r_{O}+R_{F}+r_{\pi }{\mathit {\parallel }}R_{S}}}\ i_{t}\ .}$

The base-emitter voltage v_π is then, from Ohm's law:

${\displaystyle v_{\pi }=-i_{f}\ (r_{\pi }{\mathit {\parallel }}R_{S})\ .}$

Consequently,

${\displaystyle T=g_{m}(r_{\pi }{\mathit {\parallel }}R_{S})\ {\frac {R_{D}{\mathit {\parallel }}r_{O}}{R_{D}{\mathit {\parallel }}r_{O}+R_{F}+r_{\pi }{\mathit {\parallel }}R_{S}}}\ .}$

Application in asymptotic gain model[edit]

For more information, see: Asymptotic gain model.

The overall transresistance gain of this amplifier can be shown to be:

${\displaystyle G={\frac {v_{out}}{i_{in}}}={\frac {(1-g_{m}R_{F})R_{1}R_{2}}{R_{F}+R_{1}+R_{2}+g_{m}R_{1}R_{2}}}\ ,}$

with R₁ = R_S || r_π and R₂ = R_D || r_O.

This expression can be rewritten in the form used by the asymptotic gain model, which expresses the overall gain of a feedback amplifier in terms of several independent factors that often are more easily derived separately than is the gain itself, and that often provide insight into the circuit. This form is:

${\displaystyle G=\ G_{\infty }{\frac {T}{1+T}}+G_{0}{\frac {1}{1+T}}\ \ ,}$

where the so-called asymptotic gain G_∞ is the gain at infinite g_m, namely:

${\displaystyle G_{\infty }=-R_{F}\ ,}$

and the so-called feed forward or direct feedthrough G₀ is the gain for zero g_m, namely:

${\displaystyle G_{0}={\frac {R_{1}R_{2}}{R_{F}+R_{1}+R_{2}}}\ .}$

References[edit]