In abstract algebra, an algebra extension is the ring-theoretic equivalent of a group extension.
Precisely, a ring extension of a ring R by an abelian group I is a pair (E, [math]\displaystyle{ \phi }[/math]) consisting of a ring E and a ring homomorphism [math]\displaystyle{ \phi }[/math] that fits into the short exact sequence of abelian groups:
This makes I isomorphic to a two-sided ideal of E.
Given a commutative ring A, an A-extension or an extension of an A-algebra is defined in the same way by replacing "ring" with "algebra over A" and "abelian groups" with "A-modules".
An extension is said to be trivial or to split if [math]\displaystyle{ \phi }[/math] splits; i.e., [math]\displaystyle{ \phi }[/math] admits a section that is a ring homomorphism[2] (see § Example: trivial extension).
A morphism between extensions of R by I, over say A, is an algebra homomorphism E → E' that induces the identities on I and R. By the five lemma, such a morphism is necessarily an isomorphism, and so two extensions are equivalent if there is a morphism between them.
Let R be a commutative ring and M an R-module. Let E = R ⊕ M be the direct sum of abelian groups. Define the multiplication on E by
Note that identifying (a, x) with a + εx where ε squares to zero and expanding out (a + εx)(b + εy) yields the above formula; in particular we see that E is a ring. It is sometimes called the algebra of dual numbers. Alternatively, E can be defined as [math]\displaystyle{ \operatorname{Sym}(M)/\bigoplus_{n \ge 2} \operatorname{Sym}^n(M) }[/math] where [math]\displaystyle{ \operatorname{Sym}(M) }[/math] is the symmetric algebra of M.[3] We then have the short exact sequence
where p is the projection. Hence, E is an extension of R by M. It is trivial since [math]\displaystyle{ r \mapsto (r, 0) }[/math] is a section (note this section is a ring homomorphism since [math]\displaystyle{ (1, 0) }[/math] is the multiplicative identity of E). Conversely, every trivial extension E of R by I is isomorphic to [math]\displaystyle{ R \oplus I }[/math] if [math]\displaystyle{ I^2 = 0 }[/math]. Indeed, identifying [math]\displaystyle{ R }[/math] as a subring of E using a section, we have [math]\displaystyle{ (E, \phi) \simeq (R \oplus I, p) }[/math] via [math]\displaystyle{ e \mapsto (\phi(e), e - \phi(e)) }[/math].[1]
One interesting feature of this construction is that the module M becomes an ideal of some new ring. In his book Local Rings, Nagata calls this process the principle of idealization.[4]
Especially in deformation theory, it is common to consider an extension R of a ring (commutative or not) by an ideal whose square is zero. Such an extension is called a square-zero extension, a square extension or just an extension. For a square-zero ideal I, since I is contained in the left and right annihilators of itself, I is a [math]\displaystyle{ R/I }[/math]-bimodule.
More generally, an extension by a nilpotent ideal is called a nilpotent extension. For example, the quotient [math]\displaystyle{ R \to R_{\mathrm{red}} }[/math] of a Noetherian commutative ring by the nilradical is a nilpotent extension.
In general,
is a square-zero extension. Thus, a nilpotent extension breaks up into successive square-zero extensions. Because of this, it is usually enough to study square-zero extensions in order to understand nilpotent extensions.
Original source: https://en.wikipedia.org/wiki/Algebra extension.
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