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Angelescu polynomials

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Short description: Polynomial sequence

In mathematics, the Angelescu polynomials πn(x) are a series of polynomials generalizing the Laguerre polynomials introduced by (Angelescu 1938). The polynomials can be given by the generating functionϕ(t1t)exp(xt1t)=n=0πn(x)tn.(Boas Buck)

They can also be defined by the equation πn(x):=exDn[exAn(x)],where An(x)n! is an Appell set of polynomials[which?] (see (Shukla 1981)).

Properties

Addition and recurrence relations

The Angelescu polynomials satisfy the following addition theorem:

(1)nr=0mLm+nr(n)(x)πr(y)(n+mr)!r!=r=0m(1)r(n1r)πnr(x+y)(mr)!,where Lm+nr(n) is a generalized Laguerre polynomial.

A particularly notable special case of this is when n=0, in which case the formula simplifies toπm(x+y)m!=r=0mLmr(x)πr(y)(mr)!r!r=0m1Lmr1(x)πr(y)(mr1)!r!.(Shastri 1940)[clarification needed]

The polynomials also satisfy the recurrence relation

πs(x)=r=0n(1)n+r(nr)s!(n+sr)!dndxn[πn+sr(x)],

which simplifies when n=0 to πs+1(x)=(s+1)[πs(x)πs(x)]. ((Shastri 1940)) This can be generalized to the following:

r=0s1(m+nr1)!Lm+nr1(m+n1)(x)πrs(y)(sr)!=1(m+n+s)!dm+ndxmdynπm+n+s(x+y),

a special case of which is the formula dm+ndxmdynπm+n(x+y)=(1)m+n(m+n)!a0. (Shastri 1940)

Integrals

The Angelescu polynomials satisfy the following integral formulae:

0ex/2x[πn(x)πn(0)]dx=r=0n1(1)nr+1n!r!πr(0)0[11/2+p1]nr1d[11/2+p]=r=0n1(1)nr+1n!r!πr(0)nr[1+(1)nr1]

0ex[πn(x)πn(0)]Lm(1)(x)dx={0 if mnn!(nm1)!πnm1(0) if 0mn1

(Shastri 1940)

(Here, Lm(1)(x) is a Laguerre polynomial.)

Further generalization

We can define a q-analog of the Angelescu polynomials as πn,q(x):=eq(xqn)Dqn[Eq(x)Pn(x)], where eq and Eq are the q-exponential functions eq(x):=Πn=0(1qnx)1=Σk=0xk[k]! and Eq(x):=Πn=0(1+qnx)=Σk=0qk(k1)2xk[k]![verification needed], Dq is the q-derivative, and Pn is a "q-Appell set" (satisfying the property DqPn(x)=[n]Pn1(x)). (Shukla 1981)

This q-analog can also be given as a generating function as well:

n=0πn,q(x)tn(1;n)=n=0(1)nqn(n1)2tnPn(x)(1;n)[1t]n+1,where we employ the notation (a;k):=(1qa)(1qa+k1) and [a+b]n=k=0n[nk]ankbk. (Shukla 1981)[verification needed]

References




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