Cumulative distribution function | |||
Parameters | none | ||
---|---|---|---|
Support | Cantor set, a subset of [0,1] | ||
pmf | none | ||
CDF | Cantor function | ||
Mean | 1/2 | ||
Median | anywhere in [1/3, 2/3] | ||
Mode | n/a | ||
Variance | 1/8 | ||
Skewness | 0 | ||
Kurtosis | −8/5 | ||
MGF | [math]\displaystyle{ e^{t/2} \prod_{k=1}^\infty \cosh\left(\frac{t}{3^k}\right) }[/math] | ||
CF | [math]\displaystyle{ e^{it/2} \prod_{k=1}^\infty \cos\left(\frac{t}{3^k}\right) }[/math] |
The Cantor distribution is the probability distribution whose cumulative distribution function is the Cantor function.
This distribution has neither a probability density function nor a probability mass function, since although its cumulative distribution function is a continuous function, the distribution is not absolutely continuous with respect to Lebesgue measure, nor does it have any point-masses. It is thus neither a discrete nor an absolutely continuous probability distribution, nor is it a mixture of these. Rather it is an example of a singular distribution.
Its cumulative distribution function is continuous everywhere but horizontal almost everywhere, so is sometimes referred to as the Devil's staircase, although that term has a more general meaning.
The support of the Cantor distribution is the Cantor set, itself the intersection of the (countably infinitely many) sets:
The Cantor distribution is the unique probability distribution for which for any Ct (t ∈ { 0, 1, 2, 3, ... }), the probability of a particular interval in Ct containing the Cantor-distributed random variable is identically 2−t on each one of the 2t intervals.
It is easy to see by symmetry and being bounded that for a random variable X having this distribution, its expected value E(X) = 1/2, and that all odd central moments of X are 0.
The law of total variance can be used to find the variance var(X), as follows. For the above set C1, let Y = 0 if X ∈ [0,1/3], and 1 if X ∈ [2/3,1]. Then:
From this we get:
A closed-form expression for any even central moment can be found by first obtaining the even cumulants[1]
where B2n is the 2nth Bernoulli number, and then expressing the moments as functions of the cumulants.
Original source: https://en.wikipedia.org/wiki/Cantor distribution.
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