In mathematics, the field trace is a particular function defined with respect to a finite field extension L/K, which is a K-linear map from L onto K.
Let K be a field and L a finite extension (and hence an algebraic extension) of K. L can be viewed as a vector space over K. Multiplication by α, an element of L,
is a K-linear transformation of this vector space into itself. The trace, TrL/K(α), is defined as the (linear algebra) trace of this linear transformation.[1]
For α in L, let σ1(α), ..., σn(α) be the roots (counted with multiplicity) of the minimal polynomial of α over K (in some extension field of K), then
If L/K is separable then each root appears only once[2] (however this does not mean the coefficient above is one; for example if α is the identity element 1 of K then the trace is [L:K] times 1).
More particularly, if L/K is a Galois extension and α is in L, then the trace of α is the sum of all the Galois conjugates of α,[1] i.e.,
where Gal(L/K) denotes the Galois group of L/K.
Let [math]\displaystyle{ L = \mathbb{Q}(\sqrt{d}) }[/math] be a quadratic extension of [math]\displaystyle{ \mathbb{Q} }[/math]. Then a basis of [math]\displaystyle{ L/\mathbb{Q} \text{ is }\{1, \sqrt{d}\}. }[/math] If [math]\displaystyle{ \alpha = a + b\sqrt{d} }[/math] then the matrix of [math]\displaystyle{ m_{\alpha} }[/math] is:
and so, [math]\displaystyle{ \operatorname{Tr}_{L/\mathbb{Q}}(\alpha) = [L:\mathbb{Q}(\alpha)]\left( \sigma_1(\alpha) + \sigma_2(\alpha)\right) = 1. \left( \sigma_1(\alpha) + \overline{\sigma_1}(\alpha)\right) = a+b\sqrt{d} + a-b\sqrt{d} = 2a }[/math].[1] The minimal polynomial of α is X2 − 2a X + a2 − d b2.
Several properties of the trace function hold for any finite extension.[3]
The trace TrL/K : L → K is a K-linear map (a K-linear functional), that is
If α ∈ K then [math]\displaystyle{ \operatorname{Tr}_{L/K}(\alpha) = [L:K] \alpha. }[/math]
Additionally, trace behaves well in towers of fields: if M is a finite extension of L, then the trace from M to K is just the composition of the trace from M to L with the trace from L to K, i.e.
Let L = GF(qn) be a finite extension of a finite field K = GF(q). Since L/K is a Galois extension, if α is in L, then the trace of α is the sum of all the Galois conjugates of α, i.e.[4]
In this setting we have the additional properties,[5]
Theorem.[6] For b ∈ L, let Fb be the map [math]\displaystyle{ a \mapsto \operatorname{Tr}_{L/K}(ba). }[/math] Then Fb ≠ Fc if b ≠ c. Moreover, the K-linear transformations from L to K are exactly the maps of the form Fb as b varies over the field L.
When K is the prime subfield of L, the trace is called the absolute trace and otherwise it is a relative trace.[4]
A quadratic equation, ax2 + bx + c = 0, with a ≠ 0, and coefficients in the finite field [math]\displaystyle{ \operatorname{GF}(q) = \mathbb{F}_q }[/math] has either 0, 1 or 2 roots in GF(q) (and two roots, counted with multiplicity, in the quadratic extension GF(q2)). If the characteristic of GF(q) is odd, the discriminant, Δ = b2 − 4ac indicates the number of roots in GF(q) and the classical quadratic formula gives the roots. However, when GF(q) has even characteristic (i.e., q = 2h for some positive integer h), these formulas are no longer applicable.
Consider the quadratic equation ax2 + bx + c = 0 with coefficients in the finite field GF(2h).[7] If b = 0 then this equation has the unique solution [math]\displaystyle{ x = \sqrt{\frac{c}{a}} }[/math] in GF(q). If b ≠ 0 then the substitution y = ax/b converts the quadratic equation to the form:
This equation has two solutions in GF(q) if and only if the absolute trace [math]\displaystyle{ \operatorname{Tr}_{GF(q)/GF(2)}(\delta) = 0. }[/math] In this case, if y = s is one of the solutions, then y = s + 1 is the other. Let k be any element of GF(q) with [math]\displaystyle{ \operatorname{Tr}_{GF(q)/GF(2)}(k) = 1. }[/math] Then a solution to the equation is given by:
When h = 2m + 1, a solution is given by the simpler expression:
When L/K is separable, the trace provides a duality theory via the trace form: the map from L × L to K sending (x, y) to TrL/K(xy) is a nondegenerate, symmetric, bilinear form called the trace form. An example of where this is used is in algebraic number theory in the theory of the different ideal.
The trace form for a finite degree field extension L/K has non-negative signature for any field ordering of K.[8] The converse, that every Witt equivalence class with non-negative signature contains a trace form, is true for algebraic number fields K.[8]
If L/K is an inseparable extension, then the trace form is identically 0.[9]
Original source: https://en.wikipedia.org/wiki/Field trace.
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