Field trace

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In mathematics, the field trace is a particular function defined with respect to a finite field extension L/K, which is a K-linear map from L onto K.

Definition

Let K be a field and L a finite extension (and hence an algebraic extension) of K. L can be viewed as a vector space over K. Multiplication by α, an element of L,

mα:LL given by mα(x)=αx,

is a K-linear transformation of this vector space into itself. The trace, TrL/K(α), is defined as the (linear algebra) trace of this linear transformation.[1]

For α in L, let σ1(α), ..., σn(α) be the roots (counted with multiplicity) of the minimal polynomial of α over K (in some extension field of K), then

TrL/K(α)=[L:K(α)]j=1nσj(α).

If L/K is separable then each root appears only once[2] (however this does not mean the coefficient above is one; for example if α is the identity element 1 of K then the trace is [L:K] times 1).

More particularly, if L/K is a Galois extension and α is in L, then the trace of α is the sum of all the Galois conjugates of α,[1] i.e.,

TrL/K(α)=gGal(L/K)g(α),

where Gal(L/K) denotes the Galois group of L/K.

Example

Let L=Q(d) be a quadratic extension of Q. Then a basis of L/Q is {1,d}. If α=a+bd then the matrix of mα is:

[abdba],

and so, TrL/Q(α)=[L:Q(α)](σ1(α)+σ2(α))=1.(σ1(α)+σ1(α))=a+bd+abd=2a.[1] The minimal polynomial of α is X2 − 2a X + a2d b2.

Properties of the trace

Several properties of the trace function hold for any finite extension.[3]

The trace TrL/K : LK is a K-linear map (a K-linear functional), that is

TrL/K(αa+βb)=αTrL/K(a)+βTrL/K(b) for all α,βK.

If αK then TrL/K(α)=[L:K]α.

Additionally, trace behaves well in towers of fields: if M is a finite extension of L, then the trace from M to K is just the composition of the trace from M to L with the trace from L to K, i.e.

TrM/K=TrL/KTrM/L.

Finite fields

Let L = GF(qn) be a finite extension of a finite field K = GF(q). Since L/K is a Galois extension, if α is in L, then the trace of α is the sum of all the Galois conjugates of α, i.e.[4]

TrL/K(α)=α+αq++αqn1.

In this setting we have the additional properties,[5]

  • TrL/K(aq)=TrL/K(a) for aL
  • for any αK, we have |{bL:TrL/K(b)=α}|=qn1

Theorem.[6] For bL, let Fb be the map aTrL/K(ba). Then FbFc if bc. Moreover, the K-linear transformations from L to K are exactly the maps of the form Fb as b varies over the field L.

When K is the prime subfield of L, the trace is called the absolute trace and otherwise it is a relative trace.[4]

Application

A quadratic equation, ax2 + bx + c = 0, with a ≠ 0, and coefficients in the finite field GF(q)=Fq has either 0, 1 or 2 roots in GF(q) (and two roots, counted with multiplicity, in the quadratic extension GF(q2)). If the characteristic of GF(q) is odd, the discriminant, Δ = b2 − 4ac indicates the number of roots in GF(q) and the classical quadratic formula gives the roots. However, when GF(q) has even characteristic (i.e., q = 2h for some positive integer h), these formulas are no longer applicable.

Consider the quadratic equation ax2 + bx + c = 0 with coefficients in the finite field GF(2h).[7] If b = 0 then this equation has the unique solution x=ca in GF(q). If b ≠ 0 then the substitution y = ax/b converts the quadratic equation to the form:

y2+y+δ=0, where δ=acb2.

This equation has two solutions in GF(q) if and only if the absolute trace TrGF(q)/GF(2)(δ)=0. In this case, if y = s is one of the solutions, then y = s + 1 is the other. Let k be any element of GF(q) with TrGF(q)/GF(2)(k)=1. Then a solution to the equation is given by:

y=s=kδ2+(k+k2)δ4++(k+k2++k2h2)δ2h1.

When h = 2m + 1, a solution is given by the simpler expression:

y=s=δ+δ22+δ24++δ22m.

Trace form

When L/K is separable, the trace provides a duality theory via the trace form: the map from L × L to K sending (x, y) to TrL/K(xy) is a nondegenerate, symmetric, bilinear form called the trace form. An example of where this is used is in algebraic number theory in the theory of the different ideal.

The trace form for a finite degree field extension L/K has non-negative signature for any field ordering of K.[8] The converse, that every Witt equivalence class with non-negative signature contains a trace form, is true for algebraic number fields K.[8]

If L/K is an inseparable extension, then the trace form is identically 0.[9]

See also

Notes

  1. 1.0 1.1 1.2 Rotman 2002, p. 940
  2. Rotman 2002, p. 941
  3. Roman 1995, p. 151 (1st ed.)
  4. 4.0 4.1 Lidl & Niederreiter 1997, p.54
  5. Mullen & Panario 2013, p. 21
  6. Lidl & Niederreiter 1997, p.56
  7. Hirschfeld 1979, pp. 3-4
  8. 8.0 8.1 Lorenz (2008) p.38
  9. Isaacs 1994, p. 369 as footnoted in Rotman 2002, p. 943

References

Further reading




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