In algebraic topology, homotopical connectivity is a property describing a topological space based on the dimension of its holes. In general, low homotopical connectivity indicates that the space has at least one low-dimensional hole. The concept of n-connectedness generalizes the concepts of path-connectedness and simple connectedness.
An equivalent definition of homotopical connectivity is based on the homotopy groups of the space. A space is n-connected (or n-simple connected) if its first n homotopy groups are trivial.
Homotopical connectivity is defined for maps, too. A map is n-connected if it is an isomorphism "up to dimension n, in homotopy".
All definitions below consider a topological space X.
A hole in X is, informally, a thing that prevents some suitably-placed sphere from continuously shrinking to a point.[1](p78) Equivalently, it is a sphere that cannot be continuously extended to a ball. Formally,
In general, for every integer d, [math]\displaystyle{ \text{conn}_{\pi}(S^d)=d-1 }[/math] (and [math]\displaystyle{ \eta_{\pi}(S^d)=d+1 }[/math])[1](p79) The proof requires two directions:
A space X is called n-connected, for n ≥ 0, if it is non-empty, and all its homotopy groups of order d ≤ n are the trivial group: [math]\displaystyle{ \pi_d(X) \cong 0, \quad -1 \leq d \leq n, }[/math] where [math]\displaystyle{ \pi_i(X) }[/math] denotes the i-th homotopy group and 0 denotes the trivial group.[3] The two definitions are equivalent. The requirement for an n-connected space consists of requirements for all d ≤ n:
The requirements of being non-empty and path-connected can be interpreted as (−1)-connected and 0-connected, respectively, which is useful in defining 0-connected and 1-connected maps, as below. The 0th homotopy set can be defined as:
This is only a pointed set, not a group, unless X is itself a topological group; the distinguished point is the class of the trivial map, sending S0 to the base point of X. Using this set, a space is 0-connected if and only if the 0th homotopy set is the one-point set. The definition of homotopy groups and this homotopy set require that X be pointed (have a chosen base point), which cannot be done if X is empty.
A topological space X is path-connected if and only if its 0th homotopy group vanishes identically, as path-connectedness implies that any two points x1 and x2 in X can be connected with a continuous path which starts in x1 and ends in x2, which is equivalent to the assertion that every mapping from S0 (a discrete set of two points) to X can be deformed continuously to a constant map. With this definition, we can define X to be n-connected if and only if
The corresponding relative notion to the absolute notion of an n-connected space is an n-connected map, which is defined as a map whose homotopy fiber Ff is an (n − 1)-connected space. In terms of homotopy groups, it means that a map [math]\displaystyle{ f\colon X \to Y }[/math] is n-connected if and only if:
The last condition is frequently confusing; it is because the vanishing of the (n − 1)-st homotopy group of the homotopy fiber Ff corresponds to a surjection on the nth homotopy groups, in the exact sequence:
If the group on the right [math]\displaystyle{ \pi_{n-1}(Ff) }[/math] vanishes, then the map on the left is a surjection.
Low-dimensional examples:
n-connectivity for spaces can in turn be defined in terms of n-connectivity of maps: a space X with basepoint x0 is an n-connected space if and only if the inclusion of the basepoint [math]\displaystyle{ x_0 \hookrightarrow X }[/math] is an n-connected map. The single point set is contractible, so all its homotopy groups vanish, and thus "isomorphism below n and onto at n" corresponds to the first n homotopy groups of X vanishing.
This is instructive for a subset: an n-connected inclusion [math]\displaystyle{ A \hookrightarrow X }[/math] is one such that, up to dimension n − 1, homotopies in the larger space X can be homotoped into homotopies in the subset A.
For example, for an inclusion map [math]\displaystyle{ A \hookrightarrow X }[/math] to be 1-connected, it must be:
One-to-one on [math]\displaystyle{ \pi_0(A) \to \pi_0(X) }[/math] means that if there is a path connecting two points [math]\displaystyle{ a, b \in A }[/math] by passing through X, there is a path in A connecting them, while onto [math]\displaystyle{ \pi_1(X) }[/math] means that in fact a path in X is homotopic to a path in A.
In other words, a function which is an isomorphism on [math]\displaystyle{ \pi_{n-1}(A) \to \pi_{n-1}(X) }[/math] only implies that any elements of [math]\displaystyle{ \pi_{n-1}(A) }[/math] that are homotopic in X are abstractly homotopic in A – the homotopy in A may be unrelated to the homotopy in X – while being n-connected (so also onto [math]\displaystyle{ \pi_n(X) }[/math]) means that (up to dimension n − 1) homotopies in X can be pushed into homotopies in A.
This gives a more concrete explanation for the utility of the definition of n-connectedness: for example, a space where the inclusion of the k-skeleton is n-connected (for n > k) – such as the inclusion of a point in the n-sphere – has the property that any cells in dimensions between k and n do not affect the lower-dimensional homotopy types.
Many topological proofs require lower bounds on the homotopical connectivity. There are several "recipes" for proving such lower bounds.
Hurewicz theorem relates the homotopical connectivity [math]\displaystyle{ \text{conn}_{\pi}(X) }[/math] to the homological connectivity, denoted by [math]\displaystyle{ \text{conn}_H(X) }[/math]. This is useful for computing homotopical connectivity, since the homological groups can be computed more easily.
Suppose first that X is simply-connected, that is, [math]\displaystyle{ \text{conn}_{\pi}(X)\geq 1 }[/math]. Let [math]\displaystyle{ n := \text{conn}_{\pi}(X) + 1\geq 2 }[/math]; so [math]\displaystyle{ \pi_i(X)= 0 }[/math] for all [math]\displaystyle{ i\lt n }[/math], and [math]\displaystyle{ \pi_n(X)\neq 0 }[/math]. Hurewicz theorem[5](p366) says that, in this case, [math]\displaystyle{ \tilde{H_i}(X)= 0 }[/math] for all [math]\displaystyle{ i\lt n }[/math], and [math]\displaystyle{ \tilde{H_n}(X) }[/math] is isomorphic to [math]\displaystyle{ \pi_n(X) }[/math], so [math]\displaystyle{ \tilde{H_n}(X)\neq 0 }[/math] too. Therefore:[math]\displaystyle{ \text{conn}_H(X) = \text{conn}_{\pi}(X). }[/math]If X is not simply-connected ([math]\displaystyle{ \text{conn}_{\pi}(X)\leq 0 }[/math]), then[math]\displaystyle{ \text{conn}_H(X)\geq \text{conn}_{\pi}(X) }[/math]still holds. When [math]\displaystyle{ \text{conn}_{\pi}(X)\leq-1 }[/math] this is trivial. When [math]\displaystyle{ \text{conn}_{\pi}(X)=0 }[/math] (so X is path-connected but not simply-connected), one should prove that [math]\displaystyle{ \tilde{H_0}(X)= 0 }[/math].[clarification needed]
The inequality may be strict: there are spaces in which [math]\displaystyle{ \text{conn}_{\pi}(X)=0 }[/math] but [math]\displaystyle{ \text{conn}_H(X)=\infty }[/math].[6]
By definition, the k-th homology group of a simplicial complex depends only on the simplices of dimension at most k+1 (see simplicial homology). Therefore, the above theorem implies that a simplicial complex K is k-connected if and only if its (k+1)-dimensional skeleton (the subset of K containing only simplices of dimension at most k+1) is k-connected.:[1](p80)
Let K and L be non-empty cell complexes. Their join is commonly denoted by [math]\displaystyle{ K * L }[/math]. Then:[1](p81) [math]\displaystyle{ \text{conn}_{\pi}(K*L) \geq \text{conn}_{\pi}(K)+\text{conn}_{\pi}(L)+2. }[/math]
The identity is simpler with the eta notation: [math]\displaystyle{ \eta_{\pi}(K*L) \geq \eta_{\pi}(K)+\eta_{\pi}(L). }[/math] As an example, let [math]\displaystyle{ K = L = S^0 = }[/math] a set of two disconnected points. There is a 1-dimensional hole between the points, so the eta is 1. The join [math]\displaystyle{ K * L }[/math] is a square, which is homeomorphic to a circle, so its eta is 2. The join of this square with a third copy of K is a octahedron, which is homeomorphic to [math]\displaystyle{ S^2 }[/math], and its eta is 3. In general, the join of n copies of [math]\displaystyle{ S^0 }[/math] is homeomorphic to [math]\displaystyle{ S^{n-1} }[/math] and its eta is n.
The general proof is based on a similar formula for the homological connectivity.
Let K1,...,Kn be abstract simplicial complexes, and denote their union by K.
Denote the nerve complex of {K1, ... , Kn} (the abstract complex recording the intersection pattern of the Ki) by N.
If, for each nonempty [math]\displaystyle{ J\subset I }[/math], the intersection [math]\displaystyle{ \bigcap_{i\in J} U_i }[/math] is either empty or (k−|J|+1)-connected, then for every j ≤ k, the j-th homotopy group of N is isomorphic to the j-th homotopy group of K.
In particular, N is k-connected if-and-only-if K is k-connected.[7]:{{{1}}}
In geometric topology, cases when the inclusion of a geometrically-defined space, such as the space of immersions [math]\displaystyle{ M \to N, }[/math] into a more general topological space, such as the space of all continuous maps between two associated spaces [math]\displaystyle{ X(M) \to X(N), }[/math] are n-connected are said to satisfy a homotopy principle or "h-principle". There are a number of powerful general techniques for proving h-principles.
Original source: https://en.wikipedia.org/wiki/Homotopical connectivity.
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