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1816 United States presidential election in Ohio
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| Elections in Ohio |
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The 1816 United States presidential election in Ohio took place between November 1 and December 4, 1816, as part of the 1816 United States presidential election. Voters chose 8 representatives, or electors to the Electoral College, who voted for President and Vice President.
Ohio elected Democratic-Republican candidate James Monroe over Federalist candidate Rufus King. Monroe won Ohio by a margin of 69.74%.
Results
[edit]| 1816 United States presidential election in Ohio[1] | |||||
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| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic-Republican | James Monroe | 3,326 | 84.87% | 8 | |
| Federalist | Rufus King | 593 | 15.13% | 0 | |
| Totals | 3,919 | 100.0% | 8 | ||
See also
[edit]References
[edit]- ^ Ohio. Secretary of State. (1909). Ohio election statistics: the general election. Springfield, Ohio: The Springfield Publishing Company, State Printers. p. 3. OCLC 5470967. Retrieved December 8, 2019.
State results of the 1816 United States presidential election | ||
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Licensed under CC BY-SA 3.0 | Source: https://en.wikipedia.org/wiki/1816_United_States_presidential_election_in_Ohio1 | ↧ Download as ZWI file
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