1856 United States presidential election in Vermont

1856 United States presidential election in Vermont

← 1852 November 4, 1856 1860 →

Nominee John C. Frémont James Buchanan Party Republican Democratic Home state California Pennsylvania Running mate William L. Dayton John C. Breckinridge Electoral vote 5 0 Popular vote 39,561 10,577 Percentage 77.96% 20.84%

County Results Frémont   60-70%   70-80%   80-90%

President before election Franklin Pierce Democratic Elected President James Buchanan Democratic

Elections in Vermont
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The 1856 United States presidential election in Vermont took place on November 4, 1856, as part of the 1856 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for president and vice president.

Vermont voted for the Republican candidate, John C. Frémont, over the Democratic candidate, James Buchanan, and the Know Nothing candidate, Millard Fillmore. Frémont won the state by a margin of 57.12%.

With 77.96% of the popular vote, Vermont would be his strongest victory in the Union in terms of percentage in the popular vote.^[1]

Frémont's victory also started the 104-year-long streak of Republican presidential candidate victories in Vermont, which would last for 27 consecutive presidential elections from 1856 through 1960—as of 2020, still tied with Georgia from 1852 to 1960 for the most of any state.^[2] A Democratic presidential candidate would not win Vermont until Lyndon B. Johnson won the state against Barry Goldwater 108 years later in 1964.

• United States presidential elections in Vermont

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