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1888 United States presidential election in Delaware
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| Elections in Delaware |
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The 1888 United States presidential election in Delaware took place on November 6, 1888, as part of the 1888 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.
Delaware voted for the Democratic nominee, incumbent President Grover Cleveland, over the Republican nominee, Benjamin Harrison. Cleveland won the state by a margin of 11.64%.
This was the last time until 2000 that a Republican was elected president without winning Delaware.
Results
[edit]| 1888 United States presidential election in Delaware[1] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Democratic | Grover Cleveland of New York (incumbent) | Allen Granberry Thurman of Ohio | 16,414 | 55.15% | 3 | 100.00% | ||
| Republican | Benjamin Harrison of Indiana | Levi Parsons Morton of New York | 12,950 | 43.51% | 0 | 0.00% | ||
| Prohibition | Clinton Bowen Fisk of New Jersey | John Anderson Brooks of Missouri | 399 | 1.34% | 0 | 0.00% | ||
| N/A | Others | Others | 1 | <0.01% | 0 | 0.00% | ||
| Total | 29,764 | 100.00% | 3 | 100.00% | ||||
See also
[edit]Notes
[edit]References
[edit]- ^ "1888 Presidential General Election Results - Delaware". U.S. Election Atlas. Retrieved December 23, 2013.
  | This Delaware elections-related article is a stub. You can help Wikipedia by expanding it. |
Licensed under CC BY-SA 3.0 | Source: https://en.wikipedia.org/wiki/1888_United_States_presidential_election_in_Delaware1 | ↧ Download as ZWI file
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