1888 United States presidential election in Delaware

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1888 United States presidential election in Delaware

← 1884 November 6, 1888 1892 →
 
Nominee Grover Cleveland Benjamin Harrison
Party Democratic Republican
Home state New York Indiana
Running mate Allen G. Thurman Levi P. Morton
Electoral vote 3 0
Popular vote 16,414 12,950
Percentage 55.15% 43.51%

County Results

President before election

Grover Cleveland
Democratic

Elected President

Benjamin Harrison
Republican

The 1888 United States presidential election in Delaware took place on November 6, 1888, as part of the 1888 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.

Delaware voted for the Democratic nominee, incumbent President Grover Cleveland, over the Republican nominee, Benjamin Harrison. Cleveland won the state by a margin of 11.64%.

This was the last time until 2000 that a Republican was elected president without winning Delaware.

Results

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1888 United States presidential election in Delaware[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Grover Cleveland of New York (incumbent) Allen Granberry Thurman of Ohio 16,414 55.15% 3 100.00%
Republican Benjamin Harrison of Indiana Levi Parsons Morton of New York 12,950 43.51% 0 0.00%
Prohibition Clinton Bowen Fisk of New Jersey John Anderson Brooks of Missouri 399 1.34% 0 0.00%
N/A Others Others 1 <0.01% 0 0.00%
Total 29,764 100.00% 3 100.00%

See also

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Notes

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References

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  1. ^ "1888 Presidential General Election Results - Delaware". U.S. Election Atlas. Retrieved December 23, 2013.



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