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1969 CONCACAF Championship qualification

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Main article: 1969 CONCACAF Championship

A total of 9 CONCACAF teams entered the competition,[1] eventually reduced to 8 after Haiti renounced.[2] Later on, Haiti tried to join again but the late application was rejected.[3] Honduras, El Salvador and the USA[4] did not enter.
Costa Rica (as the hosts), Guatemala (as the defending champions), the Netherlands Antilles and Trinidad and Tobago qualified automatically. Play-offs were arranged for the remaining two spots.[5]

Preliminary round

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Series One

 Mexico3–0Bermuda 
Mancilla 6', 30'
Langarica 52'

Mexico qualifies with aggregate score of 4-2.

Series Two

 Jamaica1–1Panama 
Ziadie (pen.) Tapia 46'
Panama 1–2 Jamaica
Espinoza 20' Largie 27'
Hill 85'

Jamaica qualifies with aggregate score of 3-2.

Teams qualified to the 1969 CONCACAF Championship

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References

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  1. ^ La República, 9 July 1969 – Acuerdos del Comité del IV NORCECA
  2. ^ La República, 28 August 1969 – Boletín de Comité organizador del IV torneo de la Concacaf
  3. ^ La República, 18 November 1969 – Méxicó escogió su delegación para el Cuarto Norceca
  4. ^ Soccer History USA – The Year in American Soccer - 1969
  5. ^ La República, 8 October 1969 – Será concentrada la selección para el “NORCECA”
  6. ^ Both matches played in Jamaica.


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