1992 United States presidential election in Nebraska

1992 United States presidential election in Nebraska

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Nominee George H. W. Bush Bill Clinton Ross Perot Party Republican Democratic Independent Home state Texas Arkansas Texas Running mate Dan Quayle Al Gore James Stockdale Electoral vote 5 0 0 Popular vote 344,346 217,344 174,687 Percentage 46.58% 29.40% 23.63%

County Results Bush   30–40%   40–50%   50–60%   60–70% Clinton   40–50%

President before election George H. W. Bush Republican Elected President Bill Clinton Democratic

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The 1992 United States presidential election in Nebraska took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for president and vice president.

Nebraska was won by incumbent President George H. W. Bush (R-Texas) in a landslide, with 46.58% of the popular vote over Governor Bill Clinton (D-Arkansas) with 29.40%. Businessman Ross Perot (I-Texas) finished in third, with 23.63% of the popular vote.^[1] Clinton ultimately won the national election, defeating Bush and Perot in by a large margin in the popular vote and electoral college.^[2]

This was the first election in which Nebraska allocated its electoral votes, awarding two votes to the overall winner of the state and one vote to the winner of each congressional district.^[3] As Bush won all three districts as well as the statewide popular vote, he was awarded all five electoral votes. It would not be until 2008 that there would be a split in the state's electoral votes, with Barack Obama winning one electoral vote from the 2nd district and John McCain winning the rest.

While Bush came in a strong first, the race for second place between Perot and Clinton was much more competitive. In the rural areas of the state, Perot generally ran ahead of Clinton, placing second behind Bush in 68 of Nebraska's 93 counties. In some counties in the western part of the state, Clinton was reduced to third party status, such as in Arthur county, where he polled a measly 7% of the vote to Perot's 37% and Bush's 56%. However, Clinton was able to counter this and poll second statewide by running a strong second in most of the eastern part of the state, including, critically, heavily populated Douglas and Lancaster counties. In these two counties alone, he received 108,499 votes, almost exactly half of his statewide total. Without these two counties, Perot would have beat Clinton for second with 114,039 votes to Clinton's 108,845 (Bush would still be far ahead with 209,244).^[4]

With 46.58% of the popular vote, Nebraska would give Bush his fourth-highest vote percentage in the nation after Mississippi, South Carolina and Alabama.^[5] Perot came within 5.8% of Clinton's vote share in the state, and exceeded his share in 70 of Nebraska's 93 counties,^[6] as well as in the state's heavily conservative 3rd congressional district.

Clinton became the first Democrat to win the presidency without carrying Sherman County since Grover Cleveland 100 years prior.

Bush won all three congressional districts, including one held by a Democrat.^[7]

• Dakota
• Thurston

• United States presidential elections in Nebraska
• Presidency of Bill Clinton

• Abramson, Paul; Aldrich, John; Rohde, David (1995). Change and Continuity in the 1992 Elections. CQ Press. ISBN 0871878399.