In mathematics, specifically in functional analysis and order theory , an ordered topological vector space , also called an ordered TVS , is a topological vector space (TVS) X that has a partial order ≤ making it into an ordered vector space whose positive cone
C
:=
{
x
∈
X
:
x
≥
0
}
{\displaystyle C:=\left\{x\in X:x\geq 0\right\}}
is a closed subset of X .
Ordered TVSes have important applications in spectral theory .
If C is a cone in a TVS X then C is normal if
U
=
[
U
]
C
{\displaystyle {\mathcal {U}}=\left[{\mathcal {U}}\right]_{C}}
, where
U
{\displaystyle {\mathcal {U}}}
is the neighborhood filter at the origin,
[
U
]
C
=
{
[
U
]
:
U
∈
U
}
{\displaystyle \left[{\mathcal {U}}\right]_{C}=\left\{\left[U\right]:U\in {\mathcal {U}}\right\}}
, and
[
U
]
C
:=
(
U
+
C
)
∩
(
U
−
C
)
{\displaystyle [U]_{C}:=\left(U+C\right)\cap \left(U-C\right)}
is the C -saturated hull of a subset U of X .
If C is a cone in a TVS X (over the real or complex numbers), then the following are equivalent:
C is a normal cone.
For every filter
F
{\displaystyle {\mathcal {F}}}
in X , if
lim
F
=
0
{\displaystyle \lim {\mathcal {F}}=0}
then
lim
[
F
]
C
=
0
{\displaystyle \lim \left[{\mathcal {F}}\right]_{C}=0}
.
There exists a neighborhood base
B
{\displaystyle {\mathcal {B}}}
in X such that
B
∈
B
{\displaystyle B\in {\mathcal {B}}}
implies
[
B
∩
C
]
C
⊆
B
{\displaystyle \left[B\cap C\right]_{C}\subseteq B}
.
and if X is a vector space over the reals then also:
There exists a neighborhood base at the origin consisting of convex, balanced , C -saturated sets.
There exists a generating family
P
{\displaystyle {\mathcal {P}}}
of semi-norms on X such that
p
(
x
)
≤
p
(
x
+
y
)
{\displaystyle p(x)\leq p(x+y)}
for all
x
,
y
∈
C
{\displaystyle x,y\in C}
and
p
∈
P
{\displaystyle p\in {\mathcal {P}}}
.
If the topology on X is locally convex then the closure of a normal cone is a normal cone.
If C is a normal cone in X and B is a bounded subset of X then
[
B
]
C
{\displaystyle \left[B\right]_{C}}
is bounded; in particular, every interval
[
a
,
b
]
{\displaystyle [a,b]}
is bounded.
If X is Hausdorff then every normal cone in X is a proper cone.
Let X be an ordered vector space over the reals that is finite-dimensional. Then the order of X is Archimedean if and only if the positive cone of X is closed for the unique topology under which X is a Hausdorff TVS.
Let X be an ordered vector space over the reals with positive cone C . Then the following are equivalent:
the order of X is regular.
C is sequentially closed for some Hausdorff locally convex TVS topology on X and
X
+
{\displaystyle X^{+}}
distinguishes points in X
the order of X is Archimedean and C is normal for some Hausdorff locally convex TVS topology on X .
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