Pickaway Township, Shelby County, Illinois

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Pickaway Township
Location of Illinois in the United States
Location of Illinois in the United States
Coordinates: 39°33′47″N 88°52′09″W / 39.56306°N 88.86917°W / 39.56306; -88.86917
CountryUnited States
StateIllinois
CountyShelby
OrganizedNovember 8, 1859
Area
 • Total
29.7 sq mi (77 km2)
 • Land29.7 sq mi (77 km2)
 • Water0 sq mi (0 km2)
Elevation
718 ft (219 m)
Population
 (2010)
 • Estimate 
(2016)[1]
172
 • Density6/sq mi (2/km2)
Time zoneUTC-6 (CST)
 • Summer (DST)UTC-5 (CDT)
ZIP code
XXXXX
Area code217
FIPS code17-173-59663

Pickaway Township is located in Shelby County, Illinois. As of the 2010 census, its population was 179 and it contained 74 housing units.[2]

Geography

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According to the 2010 census, the township has a total area of 29.7 square miles (77 km2), all land.[2]

Demographics

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Historical population
CensusPop.Note
2016 (est.)172[1]
U.S. Decennial Census[3]

References

[edit]
  1. ^ a b "Population and Housing Unit Estimates". Retrieved June 9, 2017.
  2. ^ a b "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Archived from the original on February 12, 2020. Retrieved May 28, 2013.
  3. ^ "Census of Population and Housing". Census.gov. Retrieved June 4, 2016.
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Licensed under CC BY-SA 3.0 | Source: https://en.wikipedia.org/wiki/Pickaway_Township,_Shelby_County,_Illinois
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