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Sherman Township, Hardin County, Iowa

From Wikipedia - Reading time: 5 min

Sherman Township
Township
Map
Coordinates: 42°20′23″N 093°24′17″W / 42.33972°N 93.40472°W / 42.33972; -93.40472
Country United States
State Iowa
CountyHardin
Area
 • Total
35.98 sq mi (93.19 km2)
 • Land35.98 sq mi (93.19 km2)
 • Water(0%) 0 sq mi ((0%) 0 km2)
Elevation
[1]
1,142 ft (348 m)
Population
 (2000)
 • Total
461
 • Density13.2/sq mi (5.1/km2)
FIPS code468 697[2][3]
GNIS feature ID0468696

Sherman Township is a township located in Hardin County, Iowa. As of the 2010 Census, its population was 738.[4][1]

History

[edit]

Sherman Township was founded in 1870.[5] It is named for William Tecumseh Sherman.[6]

References

[edit]
  1. ^ a b "US Board on Geographic Names". United States Geological Survey. October 25, 2007. Retrieved January 31, 2008.
  2. ^ "U.S. Census website". United States Census Bureau. Retrieved January 31, 2008.
  3. ^ U.S. Geological Survey Geographic Names Information System: Sherman Township, Hardin County, Iowa
  4. ^ "Find a County". National Association of Counties. Retrieved June 7, 2011.
  5. ^ Moir, William J. (1911). Past and Present of Hardin County, Iowa. Unigraphic. pp. 319.
  6. ^ History of Hardin County, Iowa. Union Publishing Company. 1883. pp. 904.
Licensed under CC BY-SA 3.0 | Source: https://en.wikipedia.org/wiki/Sherman_Township,_Hardin_County,_Iowa
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